使用BF548的PA10，PA12引脚作为外部IO中断触发，两个共用PIN1中断，同一优先级ivg8。单独初始化一个没问题，两个都初始化，只有一个能进中断ISR。

*pPINT1_ASSIGN的设置是不是有问题？不知道该如何设置

EX_INTERRUPT_HANDLER(IsrPA10)
{
*pPINT1_REQUEST = PA10;
gui_Pb9cnt++;
}

void drv_IO_0_InterruptInit(void)
{    
  
   //register interrupt routine
    register_handler(ik_ivg8, IsrPA10);
    //assign PINT1 interrupt to IVG8
    *pSIC_IAR2 &= 0xFFF0FFFFL;
    *pSIC_IAR2  = 1<<16;    
    *pSIC_IMASK0 = IRQ_PINT1;

    //enable the PB8 input driver
    *pPORTA_INEN = PA10;
    //assign PB8 to PINT0 byte 1
    *pPINT1_ASSIGN = B1MAP_PAH;

    //set to raising edge sensitivity
    *pPINT1_INVERT_CLEAR = PA10;
    *pPINT1_EDGE_SET = PA10;

    //W1C potential latches due to history
    *pPINT1_LATCH = PA10;

    //unmask interrupts
    *pPINT1_MASK_SET = PA10;

}

EX_INTERRUPT_HANDLER(IsrPA12)
{
*pPINT1_REQUEST = PA12;
gui_Pb9cnt++;
}

void drv_IO_1_InterruptInit(void)
{

  /* register interrupt routine */
    register_handler(ik_ivg8, IsrPA12);
    
    /* assign PINT1 interrupt to IVG12 */
    *pSIC_IAR2 &= 0xFFF0FFFFL;
    *pSIC_IAR2  = 1<<16;  
    
    *pSIC_IMASK0 = IRQ_PINT1;

    /* enable the PA12 input driver */
    *pPORTA_INEN = PA12;
    /* assign PA12 to PINT1 byte 1 */
    *pPINT1_ASSIGN = B1MAP_PBH;

    /* set to raising edge sensitivity */
    *pPINT1_INVERT_CLEAR  = PA12;
    *pPINT1_EDGE_SET   = PA12;
    //*pPINT0_EDGE_CLEAR = PB8;

    /* W1C potential latches due to history */
    *pPINT1_LATCH   = PA12;

    /* unmask interrupts */
    *pPINT1_MASK_SET  = PA12;

}

只初始化中断1，能进中断1的isr；只初始化中断2，能进中断2的isr；如果1、2都初始化只能进1个中断的初始化，感觉是第2个初始化把第1个初始化的参数覆盖了。

不知道我PA10和PA12共用pin1 interrupt 是不是初始化参数哪里有问题？

哪位大神帮忙看看